以下是100道分数简便计算题，涵盖乘法交换律、结合律、分配律及拆分技巧，适合六年级学生练习：
一、乘法交换律应用（10道）
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$\frac{3}{5} \times \frac{1}{6} \times 5 = \frac{3}{5} \times 5 \times \frac{1}{6} = \frac{1}{2}$
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$\frac{7}{8} \times \frac{4}{9} \times \frac{2}{7} = \frac{7}{8} \times \frac{2}{7} \times \frac{4}{9} = \frac{1}{9}$
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$\frac{5}{12} \times \frac{3}{4} \times \frac{4}{5} = \frac{5}{12} \times \frac{4}{5} \times \frac{3}{4} = \frac{1}{3}$
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$\frac{2}{3} \times \frac{5}{7} \times \frac{7}{8} = \frac{2}{3} \times \frac{5}{8} \times \frac{7}{7} = \frac{5}{12}$
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$\frac{9}{10} \times \frac{1}{2} \times \frac{5}{9} = \frac{9}{10} \times \frac{5}{9} \times \frac{1}{2} = \frac{1}{4}$
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$\frac{4}{5} \times \frac{3}{8} \times \frac{5}{4} = \frac{4}{5} \times \frac{5}{4} \times \frac{3}{8} = \frac{3}{8}$
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$\frac{7}{10} \times \frac{2}{3} \times \frac{3}{7} = \frac{7}{10} \times \frac{3}{7} \times \frac{2}{3} = \frac{1}{5}$
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$\frac{5}{6} \times \frac{4}{9} \times \frac{9}{5} = \frac{5}{6} \times \frac{9}{5} \times \frac{4}{9} = \frac{2}{3}$
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$\frac{3}{7} \times \frac{5}{8} \times \frac{8}{3} = \frac{3}{7} \times \frac{8}{3} \times \frac{5}{8} = \frac{5}{7}$
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$\frac{8}{9} \times \frac{1}{4} \times \frac{9}{8} = \frac{8}{9} \times \frac{9}{8} \times \frac{1}{4} = \frac{1}{4}$
二、乘法结合律应用（10道）
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$\frac{5}{12} \times \frac{3}{4} \times \frac{4}{5} = \frac{5}{12} \times （\frac{3}{4} \times \frac{4}{5}） = \frac{1}{4}$
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$\frac{7}{8} \times \frac{2}{3} \times \frac{3}{7} = \frac{7}{8} \times （\frac{2}{3} \times \frac{3}{7}） = \frac{1}{4}$
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$\frac{4}{5} \times \frac{9}{10} \times \frac{5}{4} = \frac{4}{5} \times （\frac{9}{10} \times \frac{5}{4}） = \frac{9}{20}$
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$\frac{3}{7} \times \frac{5}{8} \times \frac{8}{3} = \frac{3}{7} \times （\frac{5}{8} \times \frac{8}{3}） = \frac{5}{7}$
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$\frac{6}{11} \times \frac{4}{9} \times \frac{9}{6} = \frac{6}{11} \times （\frac{4}{9} \times \frac{9}{6}） = \frac{4}{11}$
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$\frac{5}{13} \times \frac{7}{10} \